A Problem on Polynomials

Let \(x_1,x_2, x_3\) be the roots of the equation \(x^3+3x+5 = 0\). What is the value of the expression \(\displaystyle\Big(x_1+\frac{1}{x_1}\Big)\)\(\displaystyle\Big(x_2+\frac{1}{x_2}\Big)\)\(\displaystyle\Big(x_3+\frac{1}{x_3}\Big)\)?

One way in which we can do this is to break up the whole of (x1+1x1)\displaystyle\Big(x_1+\frac{1}{x_1}\Big)(x2+1x2)\displaystyle\Big(x_2+\frac{1}{x_2}\Big)(x3+1x3)\displaystyle\Big(x_3+\frac{1}{x_3}\Big) and then just use the values we obtain from x3+3x+5=0x^3+3x+5 = 0 by Vieta's formula. But, this is too long and it may get wrong somewhere. Does someone have a better method of doing this, maybe by transforming the equation??

Note by Dhrubajyoti Ghosh
3 years, 10 months ago

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Comments

The expression in question can be written as (x12+1)(x22+1)(x32+1)x1x2x3=(x12+1)(x22+1)(x32+1)5 \dfrac{(x_1 ^2 + 1)(x_ 2 ^2 + 1)(x_ 3^2 + 1) }{x_1 x_2 x_3} = \dfrac{(x_1 ^2 + 1)(x_ 2 ^2 + 1)(x_ 3^2 + 1) }{-5} .

Hint: Let f(x)=x3+3x+5f(x) = x^3 + 3x + 5 . What are the roots of f(x)=0f\left( \sqrt x \right) = 0 ?

Hint 2: If g(y)=0g(y)= 0 is a polynomial with roots y1,y2,y3y_1, y_2, y_3 , then what roots does g(y1)=0g(y - 1) = 0 has?

Pi Han Goh - 3 years, 10 months ago
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