A question on trigonometry!

Find the number of solutions of the equation given below,

3sinθ+cosθ=4\sqrt{3}\sin \theta+ \cos \theta = 4

#Geometry

Note by Akshay Yadav
5 years, 5 months ago

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1 vote

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Comments

For real solutions? Answer is 0.

Just apply the Trigonometric R method.

Pi Han Goh - 5 years, 5 months ago

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Thank you very much!

Akshay Yadav - 5 years, 5 months ago

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No, this is the quickest method. \quad\quad \quad

Pi Han Goh - 5 years, 5 months ago

Since the maximum real value for sinθ\sin \theta and cosθ\cos \theta is 11, LHS cannot be larger than 3+1<4\sqrt{3}+1 < 4, therefore, there is no real root.

Chew-Seong Cheong - 5 years, 5 months ago

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Thanks! I also used the same method to solve the question in exam and wondering if it was correct or not.

Akshay Yadav - 5 years, 5 months ago

Your method is right, but the maximum value of LHS is not 3+1\sqrt3+1.

Aditya Agarwal - 5 years, 5 months ago

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I did not say that the maximum value is 3+1\sqrt{3}+1. What I meant was LHS \ne RHS.

Chew-Seong Cheong - 5 years, 5 months ago
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