Given:.Yes,that is the division equation.Try to prove that,.Try not to use any theorem for solving this.Just use simple Algebra.This is from my class textbook,it was just written as a statement and no proof was given.I came up with one which I will post afterwards.
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To prove :- If a=bq+r, then (a,b)=(b,r), where (x,y) denotes GCD of x and y. Proof:- Let (a,b)=d and (b,r)=e. Then, (a,b) =d⇒d∣a and d∣b⇒d∣a and d∣qb⇒d∣(a−qb)⇒d∣r. Hence, d∣r and d∣b⇒d∣(b,r). Similarly, (b,r) = e⇒e∣b and e∣r⇒e∣bq and e∣r⇒e∣(bq−r)⇒e∣a. Hence, e∣a and e∣b⇒e∣(a,b). We see from the boxed expressions that (a,b)∣(b,r) and (b,r)∣(a,b)⇒(a,b)=(b,r). Q.E.D.
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Very nice proof!But how did you come up with it so fast?Have you seen similar problems before?
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Yeah, I am pretty familiar with these kind of problems ! I came across problems involving proofs of gcd while doing number theory...
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I completed the proof in the same way - I personally remember the proof from "Elementary Number Theory " by Jones - It's a great book :)
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Thanks a lot for your suggestion sir 👍 ! The book is really awesome for beginners 💎 !