A Tribute to my 50 followers! Part 3

Hii everyone!

Here's my today's problem,

(Q3)There are 10 sets of 10 coins.You know that how much the coins should weigh.You know thatall the coins in one set of ten are exactly a hundredth of an ounce off,making the entire set of ten coins a tenth of an ounce off.You also know that that all the other coins weigh the correct amount. You are allowed to use an extremely accurate digital weighing machine.

What is the minimum number of times you need to use the machine to find out the faulty set? How?

#Logic

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

If any number of coins can be weighed then the answer is 1 take 1 coin from the first set 2 from the second and so on and finally find the amount of weight less than expected , if it's six hundredth of an ounce of the sixth set is at fault..,...

chaitanya Kini - 5 years, 8 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$