A trigonometry problem! NEED HELP!!

Prove that

Note by Ashley Shamidha
6 years, 2 months ago

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Comments

Please someone prove this

Ashley Shamidha - 6 years, 2 months ago

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What are the the restrictions on B and C?

Akshay Bodhare - 6 years, 2 months ago

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ABC is a triangle and A+B+C =180

Ashley Shamidha - 6 years, 2 months ago

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@Ashley Shamidha Then expand to get tanA(tanB+tanC)+tanBtanC\tan A (\tan B+\tan C) + \tan B \tan C.

It's easy to prove sinAcosBcosC=tanB+tanC\frac{\sin A} {\cos B \cos C}=\tan B + \tan C

Then after some simplification,you will get the required expression as, 1+secAsecBsecC1+\sec A \sec B \sec C, which is always greater than 2 in case of triangle.

Akshay Bodhare - 6 years, 2 months ago
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