Addition given above. A prefered method.

$Exp.=1\frac{2}{3} +2\frac{5}{6}~~separate ~out~ integers ~and~fractions. \\ Exp. =1+2+\frac{2}{3}+\frac{5}{6} ~~common~ denominator~ for~ the~ fractions~ is~6\\ \therefore Exp.=3+\frac{2*2}{3*2}+\frac{5}{6}=3+\frac{9}{6}.~~~~~gcd(9,6)=3. ~\\ \frac{9}{6}=\frac{9/3}{6/3}=\frac{3}{2}=1\frac{1}{2}\\ \therefore Exp.=3 + 1\frac{1}{2}= 4\frac{1}{2} \\ Please~ note~ that ~~ n\frac{p}{q}= n+\frac{p}{q} ~~~e.g. ~~~ 106\frac{31}{89}= 106+\frac{31}{89} $

#Algebra

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Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$