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Good question. December 30th: you were 8 years old. December 31st: you turned 9. Today is Jan 1st of the next year. This year, on December 31st you are again gonna turn 10. The next year you will turn 11.
December 30th: you were 8 years old. December 31st: you turned 9. Today is Jan 1st of the next year. This year, on December 31st you are again gonna turn 10. The next year you will turn 11. so ,simple
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
Good question. December 30th: you were 8 years old. December 31st: you turned 9. Today is Jan 1st of the next year. This year, on December 31st you are again gonna turn 10. The next year you will turn 11.
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Good solution indeed.However my younger brother's birthday is on 31st December.So this trick works on him.
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lol..
Or maybe your age is simply in base 10 and 8 respectively
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i think your solution is more creative than mine.
December 30th: you were 8 years old. December 31st: you turned 9. Today is Jan 1st of the next year. This year, on December 31st you are again gonna turn 10. The next year you will turn 11. so ,simple
so on 31st Dec of year X age = 9, (if on 30th u were 8)
31st of next year, which is the "next day", you'd be 10.
Jan 1st of the next year, u wud be 10 and that yr's dec 31 = 11 yr