I'm not really good at Algebra so I'll need a little help with this problem, thanks :) Question How many positive integers x are there such that x <522 and there exists an integer y such that 2^y-1 is a multiple of x? Help would be appreciated :) I randomly thought of this problem and my friend said it was solvable but I can't do it :D
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First, 2^y-1 cannot exceed 522 since it must be a multiple of x. I would first list the numbers that fit in.
Then find the sets of numbers that can divide numbers above. (don't know what's it called. please tell me if you know.)
x can be any numbers above. You then have to count the numbers without repeating.
example: x = 15
y can then be 8
2^y-1 = 2^8-1
= 256-1
= 255
255 / 15 = 17
therefore: 2^8-1 is a multiple of 15
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2^y-1 can exceed 522. It is a multiple of x, not a factor.
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thanks for the correction!
"I randomly thought of this problem and my friend said it was solvable" does not sound convincing.
Anyway, if x is even, there does not exist any y as an even number cannot divide an odd number. If x is odd, consider the numbers 20,21,22,...2x. By Pigeonhole Principle, since there are (x+1) numbers, two will have the same remainder. Let those two be 2a,2b, with a greater than b without loss of generality. Then 2a−2b is a multiple of x. However, that can be rewritten as 2b(2a−b−1). Since 2b and x are coprime, we know that 2a−b−1 is a multiple of x and thus (a-b) is a possible value of y.
In conclusion, there exists y if and only if x is odd. Since there are 261 odd numbers less than 522, the answer is 261.