An amazing pattern!

  1. Take any number mm (let's say 3).

  2. Write all the numbers starting from 11 in one line.

  3. Eliminate numbers at the index kk (k0(modm)k \equiv 0 \pmod{m})

  4. Now write for each index, partial sum of the numbers till that index.

  5. Eliminate numbers at the index kk (km1(modm)k \equiv m-1 \pmod{m}).

  6. Now write for each index, partial sum of the numbers till that index.

\vdots

\quad2m-1. Eliminate numbers at the index kk (k2(modm)k \equiv 2 \pmod{m}).

\quad2m. Now write for each index, partial sum of the numbers till that index.

For example, for m=3m=3,

1234567891011121312457810111313712192737486117193761182764125 \begin{array}{ c c c c c c c c c c c c c} 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 & 13\\ 1 & 2 & & 4 & 5 & & 7 & 8 & & 10 & 11 & & 13\\ 1 & 3 & & 7 & 12 & & 19 & 27 & & 37 & 48 & & 61\\ 1 & & & 7 & & & 19 & & & 37 & & & 61\\ 1 & & & 8 & & & 27 & & & 64 & & & 125\\ \end{array}

We get a sequence of nm!\displaystyle \text{We get a sequence of} \ n^m \text{!}

Prove that this happens for any number of numbers and for any natural number mm.

PS - This is not a challenge. This is seeking help.

#Combinatorics

Note by Kartik Sharma
3 years, 10 months ago

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Comments

(1) I have fixed your LaTeX. The correct code here is "\begin{array}".

(2) This result is known as Moessner's Theorem.

Jon Haussmann - 3 years, 10 months ago

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Oh I see. Thanks! I will look into the references. BTW, can you give a simplified proof?

Kartik Sharma - 3 years, 10 months ago

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@Jon Haussmann

Kartik Sharma - 3 years, 10 months ago

I'm afraid I don't know the proof. I think it's a hard result.

Jon Haussmann - 3 years, 10 months ago

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@Jon Haussmann Yeah. I am not able to find an understandable proof yet. And its generalizations to the way Conway has done in his book, is magical indeed.

Kartik Sharma - 3 years, 10 months ago

@Mark Hennings @Pi Han Goh @Ishan Singh Please also fix the latex!

Kartik Sharma - 3 years, 10 months ago

This is seriously magic. Another math-e-magical thing with which you can fascinate a primary school student and can "irritate" a mathematician.

(Another such thing is the Goldbach's Theorem).

Kartik Sharma - 3 years, 10 months ago
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