An Equality

Given that \(a,b,c>0 \), prove that

a2b2+c2+b2a2+c2+c2a2+b2≥ab+c+bc+a+ca+b. \dfrac{a^2}{b^2 + c^2} + \dfrac {b^2}{a^2+ c^2} + \dfrac{c^2}{a^2 + b^2} \geq \dfrac a{b+c} + \dfrac b{c+a} + \dfrac c{a+b} .

#Algebra

Note by Khoa Đăng
4 years, 7 months ago

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Comments

Not sure whether correct a^2>=a......1 b^2+c^2>=b+c...2 Then dividing 1 by 2 and proceeding

Aditya Thomas - 4 years, 7 months ago
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