Calcul the sum is a very interesting subject, so I present to you this one. Can you solve it ?:D
Prove that: ∀n∈N\forall{n}\in{N}∀n∈N, ∑i+j=nCni(i+1)i−1(j+1)j−1=2(n+2)n−1\displaystyle \sum_{i+j=n}C^i_n(i+1)^{i-1}(j+1)^{j-1}=2(n+2)^{n-1}i+j=n∑Cni(i+1)i−1(j+1)j−1=2(n+2)n−1.
Note by Quan Dinh 8 years, 3 months ago
Easy Math Editor
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2 \times 3
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go with pmi i.e principal of mathematical induction
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Can you write it down more clearly? Thanks!
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Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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go with pmi i.e principal of mathematical induction
Log in to reply
Can you write it down more clearly? Thanks!