This discussion board is a place to discuss our Daily Challenges and the math and science
related to those challenges. Explanations are more than just a solution — they should
explain the steps and thinking strategies that you used to obtain the solution. Comments
should further the discussion of math and science.
When posting on Brilliant:
Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.
Markdown
Appears as
*italics* or _italics_
italics
**bold** or __bold__
bold
- bulleted - list
bulleted
list
1. numbered 2. list
numbered
list
Note: you must add a full line of space before and after lists for them to show up correctly
The main problem with this is that your expression is 'completely arbitrary'. For example, I could say that
x→10limx−1021x2+5x−100=x→10lim21x+10=15.
Adapting this idea, you could arrive at any numerical answer you want. Hence, limits would be unable to resolve this issue, as it is highly dependent on the path that you arrive at the limit.
Note: A similar problem is to define 00 though limits. "Most of the time" we get 1, though if you take limx→00x, you will get 0.
Don't u know when we write [a(x-y)/(x-y)=a] it is given or we assume that, x is not equal to y...or (x-y)is not equal to zero....and only then we divide both the numerator and denominator by (x-y)...and we get =a as result...here we are seeing clearly (10-10)=0 so we cannot proceed with such a operation...and the result we would get be absolute wrong...
answer is 20!
may sound crazy. But as I go thru discussions, the fact x + y could be the answer is presented.
whenever you encounter 'zero upon zero' situation, it is of course 'indeterminate' - but it also means that is not the end. There is a real answer different from 'indeterminate'. You may arrive at it by suitable algebraic simplification / trigonometry simplification etc.
There are even a few theorems to work out the real answers
The question is not (x^2-100)/(x-10) with x tending to zero. We can interpret (100-100)/(10-10) in different ways and get different answers as Calvin said. So the answer does not necessarily have to be 20.
For eg. the question can be interpreted as lim x->10 [(x^3-9x^2-100)/(x-10)] which gives the answer as 120. So I think answer is undefined.
hi
it's not possible, you cannot divide any real by 0, so dividing 0 by it's self is one of the craziest thing I saw, since a/0 might me greater than infinit, because that infinit times 0 is still 0, but I cannot guess what might be 0/0, since it could be 023−5=0 , 01−23=1/0 or even 00 or 0^ any number ,we can accept the strictly positive ones, but not the the others , so this is particularly weird I think
We can only cancel the term taking the supposition that it is not zero. So, if you want to cancel a term you will have to assume that it is not zero. So, in this case you cannot cancel the term my friend. so, your answer is totally wrong.
Don't u know when we write (x^2-y^2)/(x-y)=(x+y) ,it is given or we assume that, x is not equal to y...or (x-y)is not equal to zero....and only then we divide both the numerator and denominator by (x-y)...and we get =(x+y) as result,..here we are seeing clearly (10-10)=0 so we cannot proceed with such a operation...and the result we would get be absolute wrong
Hey you can't divide by zero ..... there are plethora of mathematical contradictions and absurdities based on division by zero ....... If you divide by zero serious flaws creep into your logic leading to absolute fallacies
Undefined. The division of 0 is not allowed in Maths since you can get a variety of answers. Since anything mutiplied by 0 is 0, 0 divided by 0 is everything. Like wise, nothing multiplied by 0 is not 0, hence any other number divided by 0 is just not possible
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
Not exactly "undefined"; a more fitting term would be "indeterminate", because any number x multiplied by zero is zero.
How to make crazy work: Say x is a number arbitrarily close to 10 but not exactly 10. We need to find limx→10x−10x2−100=limx→10x+10=20
Log in to reply
The main problem with this is that your expression is 'completely arbitrary'. For example, I could say that
x→10limx−1021x2+5x−100=x→10lim21x+10=15.
Adapting this idea, you could arrive at any numerical answer you want. Hence, limits would be unable to resolve this issue, as it is highly dependent on the path that you arrive at the limit.
Note: A similar problem is to define 00 though limits. "Most of the time" we get 1, though if you take limx→00x, you will get 0.
UNDEFINED
Log in to reply
i wish mathematics had something better to offer :/
as from what i learned the real and specific term for 0/0 is INDETERMINATE not undefined
u can not divide anything by zero.
Log in to reply
Though on the *crazy side* {If that was what u meant by "interesting", (100−100)/(10−10) = 10(10−10)/(10−10) = 10 }
Log in to reply
no cancellation rule applies for zero
Log in to reply
Log in to reply
Log in to reply
Don't u know when we write [a(x-y)/(x-y)=a] it is given or we assume that, x is not equal to y...or (x-y)is not equal to zero....and only then we divide both the numerator and denominator by (x-y)...and we get =a as result...here we are seeing clearly (10-10)=0 so we cannot proceed with such a operation...and the result we would get be absolute wrong...
Log in to reply
many possible answers are there.....like 10,20,undefuned,etc... depending on the person who solve it...
answer is 20! may sound crazy. But as I go thru discussions, the fact x + y could be the answer is presented.
whenever you encounter 'zero upon zero' situation, it is of course 'indeterminate' - but it also means that is not the end. There is a real answer different from 'indeterminate'. You may arrive at it by suitable algebraic simplification / trigonometry simplification etc.
There are even a few theorems to work out the real answers
Log in to reply
would u please state your ' a few theorem'...i do not know it...
Log in to reply
remember ....it is the problem only (100-100)/(10-10)=?...& not anything should be thought or taken into account....
The question is not (x^2-100)/(x-10) with x tending to zero. We can interpret (100-100)/(10-10) in different ways and get different answers as Calvin said. So the answer does not necessarily have to be 20. For eg. the question can be interpreted as lim x->10 [(x^3-9x^2-100)/(x-10)] which gives the answer as 120. So I think answer is undefined.
why is sayan C spamming :\
hi it's not possible, you cannot divide any real by 0, so dividing 0 by it's self is one of the craziest thing I saw, since a/0 might me greater than infinit, because that infinit times 0 is still 0, but I cannot guess what might be 0/0, since it could be 023−5=0 , 01−23=1/0 or even 00 or 0^ any number ,we can accept the strictly positive ones, but not the the others , so this is particularly weird I think
but I guess you know all this stuff already ^^
it can be (10^{2}-10^{2})/(10-10) =(10+10)(10-10)/(10-10) =20
Log in to reply
how can you cancel zero by zero?????
Log in to reply
i agree with that point
It can be 20 :
https://brilliant.org/discussions/thread/an-interesting-question/#comment-a3f52161e92
We can only cancel the term taking the supposition that it is not zero. So, if you want to cancel a term you will have to assume that it is not zero. So, in this case you cannot cancel the term my friend. so, your answer is totally wrong.
Don't u know when we write (x^2-y^2)/(x-y)=(x+y) ,it is given or we assume that, x is not equal to y...or (x-y)is not equal to zero....and only then we divide both the numerator and denominator by (x-y)...and we get =(x+y) as result,..here we are seeing clearly (10-10)=0 so we cannot proceed with such a operation...and the result we would get be absolute wrong
Hey you can't divide by zero ..... there are plethora of mathematical contradictions and absurdities based on division by zero ....... If you divide by zero serious flaws creep into your logic leading to absolute fallacies
Undefined. The division of 0 is not allowed in Maths since you can get a variety of answers. Since anything mutiplied by 0 is 0, 0 divided by 0 is everything. Like wise, nothing multiplied by 0 is not 0, hence any other number divided by 0 is just not possible
UNDEFINED
0/0
(100-100)/(10-10) is nothing but indeterminate form ....which cannot be solved...we may solve it using limits
and UNDEFINED tooo
It is Undetermined or Undefined.
indeterminate
cant be determined
use limit bro
0
10(10-10)/(10-10) = 10