An interesting thing everyone must know..

$0.99999....=1$! Why? It was proven in many methods, even though its logically unequal. Try the basic one, the same method as making infinitesimals to fraction. Assuming $x=0.9999...$. Then $10x=9.9999...$. Subtracting: \[10x-x=9.9999...-0.9999...\] \[9x=9\] \[x=1\] Even though we clearly declare x as 0.999..., The end result is one.

#NumberTheory #Interesting

Easy Math Editor

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Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

This is very interesting, but I don't sure how does it.!!

Golam Mohammad Kibria - 6 years, 2 months ago

We also know that $\frac{1}{3} = 0.33333...$ . Multiplying both sides by $3$ gives: $\frac{3}{3} = 0.99999...$ , or $1=0.99999...$ .

Patrick Prochazka - 5 years, 11 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$