An Olympiad Problem

Show that the equation has infinite integer solution : x2+y2+z2=(xy)(yz)(zx)x^2 + y^2 + z^2 = (x - y)(y - z)(z - x) .

#NumberTheory

Note by Dev Sharma
5 years, 9 months ago

No vote yet
1 vote

  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

  • Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
  • Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
  • Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
  • Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

Interesting question. What have you tried?

Calvin Lin Staff - 5 years, 9 months ago

Log in to reply

first of all, i want to thank you as you edited my que.. I tried but couldn't get any pattern.. And nobody is giving solution.

Dev Sharma - 5 years, 9 months ago

Log in to reply

Try listing out a few small solutions. E.g. (0,0,0),(1,0,1),(1,1,2),(2,1,1) (0, 0, 0), (-1, 0, 1), ( -1, 1, 2), (-2, -1, 1 ) . Are there any others?

Calvin Lin Staff - 5 years, 9 months ago

I started the question by applying the substitution y=x+a,z=x+a+by=x+a, z=x+a+b. We will restrict a,ba,b to be positive integers. This will give us a quadratic in xx which I omit here. My first thought, a lucky one, was to look at the case a=ba=b: 3x2+6ax+5a22a33x^2+6ax+5a^2-2a^3. After the quadratic we have:

x=a±a6(a1)3x=-a\pm \frac{a\sqrt {6(a-1)}}{3}.

We want xx to be an integer, so a1=6n2a-1=6n^2 for some integer nn.

Hence x=(6n2+1)(1±2n)x=(6n^2+1)(-1\pm 2n), y=(6n2+1)(1±2n)+6n2+1,z=(6n2+1)(1±2n)+2(6n2+1)y=(6n^2+1)(-1\pm 2n)+6n^2+1, z=(6n^2+1)(-1\pm 2n)+2(6n^2+1). nn is an integer so we can generate an infinite number of integer solutions.

In all the proving infinite solution problems I've encountered in the past, a majority of them required looking at special cases; this should be a natural approach especially for an olympiad problem. The most complicated one I've dealt with involved special cases and pell's equation, can't remember the exact problem tho.

Xuming Liang - 5 years, 9 months ago

Log in to reply

Thanks.

but why did you make y = x + a ....? and why only one case a = b??

Dev Sharma - 5 years, 9 months ago

Log in to reply

the substitution is motivated by the product of differences on the right. I only examine the a=ba=b because that's all it suffices to show the infinitude of the solutions.

Xuming Liang - 5 years, 9 months ago
×

Problem Loading...

Note Loading...

Set Loading...