Prove that, for every integer n≥1n\geq1n≥1, the quantity
(2n−1)(2n−2)(2n−22)(2n−23)⋯(2n−2n−1)n!\frac{(2^n-1)(2^n-2)(2n-2^2)(2^n-2^3)\cdots(2^n-2^{n-1})}{n!}n!(2n−1)(2n−2)(2n−22)(2n−23)⋯(2n−2n−1)
is an integer.
Source: Aha! Solutions by Martin Erickson
Note by Jane Maleza 1 year, 9 months ago
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2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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There are no comments in this discussion.