Find the type of progression formed by the angle between the tangents to a circle drawn from points which are collinear and at equal distances from each other as depicted.
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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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All I got is that cosec of half of angles are in AP.
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That's interesting. Will you please let me know about the working part?
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I am not sure that you wanted what I have written above but it was pretty easy to get
Draw a line passing through centre and all the points
Let the radius of circle be R, distance between centre and first point be d and distance between consecutive points be x
We will take triangle formed by centre, point of contact and the first point(right angled triangle)
Let the original first angle be θ then the angle of triangle be θ/2
And we will get sin(θ/2)=dR.
Similarly for next angle sin(θ1/2)=d+xR
And for next sin(θ2/2)=d+2xR
Now rest is easy just flip them to make cosec and eliminate R,d,x to get desired result :)
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You should mention what the curve is. It doesn't quite seem like a circle to me, but that might be because of the straight lines.
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Done! :)