Any solution anyone?

Need Help !!

#Geometry

Note by Syed Baqir
5 years, 9 months ago

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Comments

Im getting the answer as

πab4(a2+b2):0.5\frac{\pi ab}{4\left(a^2+b^2\right)}:0.5

So, first, the area of the rhombus is 12ab\frac{1}{2}ab

Now, to find the area of the circle, we can first find the radius of the circle.

Let the center of the circle be at coordinate (0,0)(0,0). and one of the rhombus's side be described with the equation y=ab(xb2)+ay=\frac{a}{b}\left(x-\frac{b}{2}\right)+a

The radius will be the shortest distance between the center of the circle and the side of the rhombus. Finding that distance, we get r2=a2b24(a2+b2)r^{2}=\frac{a^2b^2}{4\left(a^2+b^2\right)} The area of the circle is therefore  π×a2b24(a2+b2)\ \pi \times \frac{a^2b^2}{4\left(a^2+b^2\right)}

Hence, the ratio is πab4(a2+b2):0.5\boxed{\frac{\pi ab}{4\left(a^2+b^2\right)}:0.5}

Julian Poon - 5 years, 9 months ago

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You can write it as:

πab2(a2+b2) \frac{\pi ab}{2(a^{2}+b^{2})}

Syed Baqir - 5 years, 9 months ago

Can you elaborate more how you succeeded in finding the radius of circle,

It will be helpful if you add more lines , Thanks , (Upvoted)

Syed Baqir - 5 years, 9 months ago

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Let the x-coordinate of the point where the circle will touch the side be x0x_{0}. Now, for a certain point on the side of the rhombus, the coordinates will be (k,ab(kb2)+a)\left(k,\frac{a}{b}\left(k-\frac{b}{2}\right)+a\right). The distance between that point and the origin can thus be found using Pythagoras theorem and is given as:

k2+(ab(kb2)+a)2\sqrt{k^2+\left(\frac{a}{b}\left(k-\frac{b}{2}\right)+a\right)^2}

When k=x0k=x_{0}, the above equation would be minimised. Note that x02+(ab(x0b2)+a)2=r\sqrt{x_{0}^2+\left(\frac{a}{b}\left(x_{0}-\frac{b}{2}\right)+a\right)^2}=r, where r is the radius of the circle.

In order to find the minimum, we can find the minimum of k2+(ab(kb2)+a)2k^2+\left(\frac{a}{b}\left(k-\frac{b}{2}\right)+a\right)^2, where x02+(ab(x0b2)+a)2=r2x_{0}^2+\left(\frac{a}{b}\left(x_{0}-\frac{b}{2}\right)+a\right)^2=r^{2}

All we have to do to find r2r^{2} is to simplify the quadratic and find the minimum.

This might help.

Julian Poon - 5 years, 9 months ago

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@Julian Poon Thank you very much :D

By the way the Co-ordinate is too complicated to spot !!

Syed Baqir - 5 years, 9 months ago
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