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Comments
Im getting the answer as
4(a2+b2)πab:0.5
So, first, the area of the rhombus is 21ab
Now, to find the area of the circle, we can first find the radius of the circle.
Let the center of the circle be at coordinate (0,0). and one of the rhombus's side be described with the equation y=ba(x−2b)+a
The radius will be the shortest distance between the center of the circle and the side of the rhombus. Finding that distance, we get r2=4(a2+b2)a2b2 The area of the circle is therefore π×4(a2+b2)a2b2
Let the x-coordinate of the point where the circle will touch the side be x0. Now, for a certain point on the side of the rhombus, the coordinates will be (k,ba(k−2b)+a). The distance between that point and the origin can thus be found using Pythagoras theorem and is given as:
k2+(ba(k−2b)+a)2
When k=x0, the above equation would be minimised. Note that x02+(ba(x0−2b)+a)2=r, where r is the radius of the circle.
In order to find the minimum, we can find the minimum of k2+(ba(k−2b)+a)2, where x02+(ba(x0−2b)+a)2=r2
All we have to do to find r2 is to simplify the quadratic and find the minimum.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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\(
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or\[
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
Im getting the answer as
4(a2+b2)πab:0.5
So, first, the area of the rhombus is 21ab
Now, to find the area of the circle, we can first find the radius of the circle.
Let the center of the circle be at coordinate (0,0). and one of the rhombus's side be described with the equation y=ba(x−2b)+a
The radius will be the shortest distance between the center of the circle and the side of the rhombus. Finding that distance, we get r2=4(a2+b2)a2b2 The area of the circle is therefore π×4(a2+b2)a2b2
Hence, the ratio is 4(a2+b2)πab:0.5
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You can write it as:
2(a2+b2)πab
Can you elaborate more how you succeeded in finding the radius of circle,
It will be helpful if you add more lines , Thanks , (Upvoted)
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Let the x-coordinate of the point where the circle will touch the side be x0. Now, for a certain point on the side of the rhombus, the coordinates will be (k,ba(k−2b)+a). The distance between that point and the origin can thus be found using Pythagoras theorem and is given as:
k2+(ba(k−2b)+a)2
When k=x0, the above equation would be minimised. Note that x02+(ba(x0−2b)+a)2=r, where r is the radius of the circle.
In order to find the minimum, we can find the minimum of k2+(ba(k−2b)+a)2, where x02+(ba(x0−2b)+a)2=r2
All we have to do to find r2 is to simplify the quadratic and find the minimum.
This might help.
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By the way the Co-ordinate is too complicated to spot !!