The following is taken from the 2nd round of the 2014 South African Maths Olympiad:
How many times in a 24-hour day do the hands on a 12-hour clock point in exactly the same direction?
I am unsure about the answer which they give as 22.
What answer do you get?
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
The angular velocity of the minute hand and hour hand are ωm=2π hr−1 and ωh=122πhr−1, respectively.
The first intersection will occur when ωmt−2π=ωht, i.e. when t=ωm−ωh2π≈1.09 hr.
As soon as an intersection happens, we have the same problem again, and the next intersection will take the same amount of time as the first. 24/1.09≈22.02 which means the crossing will occur 22 times..
Log in to reply
That's Brilliant
Why isn't it ωmt−2π=ωht? I mean, the LHS shows the distance traveled by the minute hand minus one circumference and the RHS shows the path traveled by the hour hand, which is speed times time.
Log in to reply
Typo, you are right
Log in to reply
t and then we have t≈1.09hr (1213 becomes 1112) instead, but that doesn't change the answer.
That means you'll have to change the expression ofLog in to reply
An intuitive answer that I haven't found justification for:
In 12 hours, the minute hand travels 12 times the circumference and the hour hand travels 1 time, so the minute hand will cross the hour hand 11 times, and those crossings are exactly when the two hands point in the same direction. Just multiply this by 2 since there are 24 hours.
Log in to reply
Thanks for the clear explanation @josh silverman provided more than enough justification
Do they seriously give such easy question in the S.A M.O? I could solve this even 3 years back!
Log in to reply
2nd round 2nd question but there's also a 3rd round and a camp in the junior section
Log in to reply
U must take a look at India's M.O papers at AoPS.. They are far more tougher than this!
Log in to reply
Log in to reply
Log in to reply
here
u can get themLog in to reply
24
Log in to reply
I also thought that,but remembered the second hand.