ASTRONAUT Curve

Sorry I posted this as a question.

Link to Desmos -\( \url{https://www.desmos.com/calculator/nwyqmc0xlf}\)

THE EQUATION IS BELOW ->

Its confusing to see but like The Batman Curve this is a product of different curves but unlike Batman Curve , you can plot this on DESMOS also!

((∣x∣−18)2+(y−11)2−2.25)((∣x∣−18)2+(y−7)2−2.25)\left(\left(\left|x\right|-18\right)^{2}+\left(y-11\right)^{2}-2.25\right)\left(\left(\left|x\right|-18\right)^{2}+\left(y-7\right)^{2}-2.25\right)

(∣x+182+y−9.54.5∣+∣x+182−y−9.54.5∣−2)(∣x−182+y−9.54.5∣+∣x−182−y−9.54.5∣−2)\left(\left|\dfrac{x+18}{2}+\dfrac{y-9.5}{4.5}\right|+\left|\dfrac{x+18}{2}-\dfrac{y-9.5}{4.5}\right|-2\right)\left(\left|\dfrac{x-18}{2}+\dfrac{y-9.5}{4.5}\right|+\left|\dfrac{x-18}{2}-\dfrac{y-9.5}{4.5}\right|-2\right)

(((∣x∣−2+∣∣x∣−2∣23)2+(y20)2)+((x23)2+(∣y∣−2+∣∣y∣−2∣20)2)−1.5)\left(\left(\left(\dfrac{\left|x\right|-2+\left|\left|x\right|-2\right|}{23}\right)^{2}+\left(\dfrac{y}{20}\right)^{2}\right)+\left(\left(\dfrac{x}{23}\right)^{2}+\left(\dfrac{\left|y\right|-2+\left|\left|y\right|-2\right|}{20}\right)^{2}\right)-1.5\right)

(((∣x∣−2+∣∣x∣−2∣24)2+(y21)2)+((x24)2+(∣y∣−2+∣∣y∣−2∣21)2)−1.5)\left(\left(\left(\dfrac{\left|x\right|-2+\left|\left|x\right|-2\right|}{24}\right)^{2}+\left(\dfrac{y}{21}\right)^{2}\right)+\left(\left(\dfrac{x}{24}\right)^{2}+\left(\dfrac{\left|y\right|-2+\left|\left|y\right|-2\right|}{21}\right)^{2}\right)-1.5\right)

((x+10)2+(y−4)2−5)((x+8)2+(y−8)2−1)(∣x+171+y−23∣+∣x+171−y−23∣−2)\left(\left(x+10\right)^{2}+\left(y-4\right)^{2}-5\right)\left(\left(x+8\right)^{2}+\left(y-8\right)^{2}-1\right)\left(\left|\dfrac{x+17}{1}+\dfrac{y-2}{3}\right|+\left|\dfrac{x+17}{1}-\dfrac{y-2}{3}\right|-2\right)

(∣x−171+y−23∣+∣x−171−y−23∣−2)\left(\left|\dfrac{x-17}{1}+\dfrac{y-2}{3}\right|+\left|\dfrac{x-17}{1}-\dfrac{y-2}{3}\right|-2\right)

(((∣x∣−2+∣∣x∣−2∣26)2+(y−427)2)+((x26)2+(∣y∣−2+∣∣y∣−2∣−127)2)−1.5)\left(\left(\left(\dfrac{\left|x\right|-2+\left|\left|x\right|-2\right|}{26}\right)^{2}+\left(\dfrac{y-4}{27}\right)^{2}\right)+\left(\left(\dfrac{x}{26}\right)^{2}+\left(\dfrac{\left|y\right|-2+\left|\left|y\right|-2\right|-1}{27}\right)^{2}\right)-1.5\right)

(105(y−14)((y−14)−0.5(1−∣∣x+18∣−1∣∣x+18∣−1)−0.5((x+18)(∣x+18∣x+18)−2)(∣−∣x+18∣+1∣−∣x+18∣+1+∣∣x+18∣−2∣∣x+18∣−2))+1)\left(10^{5}\left(y-14\right)\left(\left(y-14\right)-0.5\left(1-\dfrac{\left|\left|x+18\right|-1\right|}{\left|x+18\right|-1}\right)-0.5\left(\left(x+18\right)\left(\dfrac{\left|x+18\right|}{x+18}\right)-2\right)\left(\dfrac{\left|-\left|x+18\right|+1\right|}{-\left|x+18\right|+1}+\dfrac{\left|\left|x+18\right|-2\right|}{\left|x+18\right|-2}\right)\right)+1\right)

(105(y−14)((y−14)−0.5(1−∣∣x−18∣−1∣∣x−18∣−1)−0.5((x−18)(∣x−18∣x−18)−2)(∣−∣x−18∣+1∣−∣x−18∣+1+∣∣x−18∣−2∣∣x−18∣−2))+1)\left(10^{5}\left(y-14\right)\left(\left(y-14\right)-0.5\left(1-\dfrac{\left|\left|x-18\right|-1\right|}{\left|x-18\right|-1}\right)-0.5\left(\left(x-18\right)\left(\dfrac{\left|x-18\right|}{x-18}\right)-2\right)\left(\dfrac{\left|-\left|x-18\right|+1\right|}{-\left|x-18\right|+1}+\frac{\left|\left|x-18\right|-2\right|}{\left|x-18\right|-2}\right)\right)+1\right)

(∣x+13.72.3+y−140.5∣+∣x+13.72.3−y−140.5∣−2)\left(\left|\dfrac{x+13.7}{2.3}+\dfrac{y-14}{0.5}\right|+\left|\dfrac{x+13.7}{2.3}-\dfrac{y-14}{0.5}\right|-2\right)

(∣x−13.72.3+y−140.5∣+∣x−13.72.3−y−140.5∣−2)=0\left(\left|\dfrac{x-13.7}{2.3}+\dfrac{y-14}{0.5}\right|+\left|\dfrac{x-13.7}{2.3}-\dfrac{y-14}{0.5}\right|-2\right)=0

Note by Niraj Sawant
1 year, 6 months ago

No vote yet
1 vote

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Comments

This is niceeeee. How did you come up with such a beastly expression on your own???

Aaghaz Mahajan - 1 year, 6 months ago

Trial and Error, I basically played around with equations a lot, took me over a month !

Niraj Sawant - 9 months, 2 weeks ago
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