Consider a pencil that stands upright on its tip and then falls over. Let’s idealize the pencil as a mass sitting at the end of a mass less rod of length
Assume that the pencil makes an initial (small) angle with the vertical, and that its initial angular speed is . The angle will eventually become large, but while it is small (so that ), what is as a function of time?
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First tell whether slipping is taking place or not, and if it is taking place , is the surface frictionless.
If slipping is not taking place , then , take moment about lowest point.
mglsinθ = ml2α [Using : sinθ=θ]
⇒dt2d2θ=lgθ
Solve this 2nd order differential equation to get :
⇒θ=2θ0+w0glelgt+2θ0−w0gle−lgt
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How did you solve the differential equation?
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Something known as wolfram :)
Actually, 2nd order diff. equations aren't taught in class 12th.
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I did not recheck my calculation so answer that I am posting might be wrong. My answer is θ(t)=θ0cosh(ωt)+ωω0sinh(ωt) for small θ. Here ω=lg and θ0 is an initial angular displacement.