Batteries with 0 resistance in parallel

What would happen in a circuit like this, both theoretically and in real life?

Would the voltage difference across the points A and B be

1V
2V
something in between 1V and 2V?

Any insight for a circuit like this would be helpful.

Thanks!

Clarification

Two batteries of 1V and 2V are connected in parallel with a 1ohm resistor.

#Physics #Electronics #Circuit

Easy Math Editor

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Comments

You need to consider the internal resistances of the batteries in situations like this. If you draw each battery as an emf and a resistor in series you will be able to get a consistent solution for the current and voltages via Kirchhoff's laws.

David Mattingly Staff - 6 years, 11 months ago

I had the same doubt some time ago... Our professor told us that the properties of batteries themselves will change making them incapable of maintaining the potential difference they were made for. I don't know how. I'm not really sure that this happens too. Can someone help us out?

Siddharth Brahmbhatt - 6 years, 11 months ago

@David Mattingly Please help us out.

Lokesh Sharma - 6 years, 11 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$