BUCKYBALL. .....THAT'S FULLERENCE

U all know the No. Of five member rings & six member rings in fullerence that is 12 & 20 respectively. But have u ever tried to find that how it came. ...

...Answer -observe the structure of fullerence. Each C atom contributs it ' 2/3 part in two six member rings. & remaining 1 / 3part is in the five member ring so each 6 member ring is made up of net 2 C atoms & five member ring is made up of net 5 / 3 C atoms. Out of 60 C atoms net 40 atoms forms six member rings.& remaining 20 atoms form five member rings. ...so

NO. Of 6 member rings = 40 / 2 = 20 & NO. Of five member rings = 20 divided by 5 / 3 = 12. ..

#Chemistry

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Comments

What about the Boron Fullerene? B40 if I am not mistaken...

Hetansh Mehta - 5 years, 10 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$