Imaginary Numbers' Powers (for those just because)

Imaginary numbers are represented by $i$ . It may seem hard to calculate $i^{243}$ at first glance because you know, 243 is a high number, so it would be natural to assume it would be hard, but it is actually simple! $i$ = $\sqrt -1$ . The first four powers of $i$ would be:

$i^{0}$ = 1
$i$ = $\sqrt -1$ or $i$
$i^{2}$ = $-1$
$i^{3}$ = $-i$

This means that $i^{243}$ would equal $-i$ .

(I know there are many people that know this, but why not?)

#Algebra

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
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Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$