calculus

Let S be a finite subset of rational number (Q) S ={x1,x2,x3.......xn} and f(x)=x-1∖x. Define R1 = {f(x1),f(x2),f(x3).......f(x4)} and S1= R1∩S R2 = {f(f(x1) ,f(f(x2 ) , f(f(x3 ) , .......f(f(xn ) and S2 =R2∩S and so on (S do not contain -1,0,1), prove that there exists (n∈N) such that Sn = Sn+1 = Sn+2 = ........∞=φ

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

let me see which brilliant mind is able to solve this..

gopal chpidhary - 7 years, 6 months ago

Is f(x) = (x - 1)/x?

John Ashley Capellan - 7 years, 6 months ago

no it's [ (x)-(1/x)]...please try it

gopal chpidhary - 7 years, 6 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$