Can I have an answer please ??

Give situations to show that square root of a^2 is not equal to a. And use this to show that square root of a^2 is equal to the absolute value of a.

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

I think it has something to do with induction ? Am I right ? But I dont know where to start. ..

Noel Quirol - 7 years, 10 months ago

I can't see how your problem has anything to do with induction.

Start with the definition of square roots. From what I understand, you're supposed to show examples. That shouldn't be tough.

A hint that makes it really easy:

What is $\sqrt{(-4)^2}$ ?

Mursalin Habib - 7 years, 10 months ago

Absolute value of a real number is it's distance from 0. If you have a point on the real line, call that point P. Let the origin be O, imagine a square with its base PO. What is the length of this square?
Induction is for natural numbers but I think there is this paper on using induction argument on statements defined on the set of real numbers.

Okay Nho - 7 years, 10 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$