If the pair of lines 6x2−pxy−3y2−24x+3y+q=06x^2-pxy-3y^2-24x+3y+q=06x2−pxy−3y2−24x+3y+q=0 intersect on x- axis then p is equal to :- a)3/2a)3/2a)3/2 b)−5/2b)-5/2b)−5/2 c)−18c)-18c)−18 d)−7d)-7d)−7
Please post the solution in DETAIL...
Note by Parag Zode 6 years, 7 months ago
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For to intersect this pair of straight line on x-axis , Let They intersect at point P (α 0\alpha \, 0α0 )
So putting y=0 in given equation
6α2−24α+q=06\alpha ^{ 2 }\quad -\quad 24\alpha \quad +\quad q\quad =\quad 06α2−24α+q=0.
Now since Intersection point is unique so value of α\alpha α is also unique. So Discriminant of this quadratic equation is zero !!
q=24α=2q\quad =\quad 24\\ \\ \alpha \quad =\quad 2q=24α=2.
Therefore Given equation representing pair of straight lines if it's Discriminant is zero !!
∣6−p/2−12−p/2−33/2−12324∣=0P=3/2\left| \begin{matrix} 6 & -p/2 & -12 \\ -p/2 & -3 & 3/2 \\ -12 & 3 & 24 \end{matrix} \right| \quad =\quad 0\\ \\ P\quad =\quad 3/2∣∣∣∣∣∣6−p/2−12−p/2−33−123/224∣∣∣∣∣∣=0P=3/2.
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Ok! I didn't knew to use determinant after finding q and a(alpha).. Anyways ,Nice solution.
The line(s) intersect the x-axis when y=0. The equation then becomes 6x^2 - 24x + q = 0. There are tons of values for x that will solve this equation depending on the value of q.
If y = 0 then values for p are limitless (infinite).
Sir but can we assume that for finding value of q the equation6x2−24x+q=06x^2-24x+q=06x2−24x+q=0 should be perfect square ? If it is then the value of q is equal to 24. This is a JEE Question .
Are there 2 lines? I see only 1 equation.
The equation above is multiplication of those 2 lines
What are the 2 lines?
@Guiseppi Butel – That is what we have to find in terms of 'p'
@Krishna Sharma – You also have a q which affects the situation.
If this line intersects the x axis then the value for y = 0.
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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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2^{34}
a_{i-1}
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\sin \theta
\boxed{123}
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For to intersect this pair of straight line on x-axis , Let They intersect at point P (α0 )
So putting y=0 in given equation
6α2−24α+q=0.
Now since Intersection point is unique so value of α is also unique. So Discriminant of this quadratic equation is zero !!
q=24α=2.
Therefore Given equation representing pair of straight lines if it's Discriminant is zero !!
∣∣∣∣∣∣6−p/2−12−p/2−33−123/224∣∣∣∣∣∣=0P=3/2.
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Ok! I didn't knew to use determinant after finding q and a(alpha).. Anyways ,Nice solution.
The line(s) intersect the x-axis when y=0. The equation then becomes 6x^2 - 24x + q = 0. There are tons of values for x that will solve this equation depending on the value of q.
If y = 0 then values for p are limitless (infinite).
Log in to reply
Sir but can we assume that for finding value of q the equation6x2−24x+q=0 should be perfect square ? If it is then the value of q is equal to 24. This is a JEE Question .
Are there 2 lines? I see only 1 equation.
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The equation above is multiplication of those 2 lines
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What are the 2 lines?
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If this line intersects the x axis then the value for y = 0.