Can You Answer This?

I need your help. Can you answer this one?

Find the value of B for any real numbers A and B such that

A + B = $A^{2}$ - $B^{2}$ = AB ≠ 0 .a

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

$\alpha+\beta = \alpha^{2}-\beta^{2}\ = (\alpha+\beta)(\alpha-\beta)$ Here, if $\alpha+\beta = 0$ , the equation will be true, therefore one of the answer is $\beta = -\alpha$ , but if $\alpha+\beta \neq 0$ , you will get $1 = \alpha-\beta$ or $\beta = \alpha-1$ . $\beta$ may be represented as $\beta = -\alpha, \alpha-1$

Kay Xspre - 5 years, 9 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$