Thanks everyone who participated. For those of you who were waiting to snipe at the last possible moment, tough luck.
You can discuss strategies and results in this discussion.
The goal is to post a (real) number from 0 to 100 (inclusive) that is closest to 0.9 times the average of every number posted.
Clearly, the later you post the more information you will get. However, the catch is that this discussion will be closed at some time within the next 24-48 hours, and no further entries will be accepted.
Participation rules:
1) Your entry should be a reply to my comment "Post your entries here".
2) Only 1 entry per person.
3) You can post whenever this note is live. It will be locked within the next 24-48 hours.
4) You may not edit your entry.
5) Have fun!
Feel free to make comments discussing this topic, or advocating people to post a certain number.
Results
Congrats to Math Math and Ahaan Rungta for being the closest!
Number of participants: 25
Average: 18.944
0.9 * ave : 17.0499
Raw results: Values have been rounded down to 3 decimal places
Name | Entry | Absolute Difference |
Math Man | 8.539 | 8.510 |
Sharky Kesa | 22.722 | 5.672 |
Daniel Liu | 9.869 | 7.180 |
Mietantei Conan | 10 | 7.049 |
Yannick Yao | 31.006 | 13.956 |
Anthony Susevski | 13.413 | 3.636 |
Tan Li Xuan | 21.415 | 4.365 |
Ahaan Rungta | 16 | 1.049 |
Aneesh Kundu | 19.911 | 2.861 |
Victor Song | 38.660 | 21.610 |
Andy Hayes | 14.771 | 2.278 |
Math Math | 16.581 | 0.468 |
Raj Magesh | 14.106 | 2.943 |
Victor Martin | 29.1 | 12.050 |
Enrique Naranjo Bejarano | 42 | 24.950 |
Samuraiwarm Tsunayoshi | 42.377 | 25.327 |
Zhijie Goh | 28 | 10.950 |
Bogdan Simeonov | 2.685 | 14.364 |
Tan Wee Kean | 20.678 | 3.628 |
Daniel Ploch | 0 | 17.049 |
Pranshu Gaba | 15.154 | 1.895 |
Justin Wong | 1 | 16.049 |
John Muradeli | 0.616 | 16.433 |
Chung Kevin | 10 | 7.049 |
Ajala Singh | 45 | 27.950 |
Entries which did not follow the participation rules have been ignored.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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2^{34}
a_{i-1}
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Comments
Post your entries here
pi∗e
pi is phi
You mean ϕ×e ?
Hmm... I work that out to be about 4.3982723895
π2
e−ϕ25 just because I can.
45
10
@John Muradeli said 16π2.
1
ee
0
My number is r such that r is equal to the maximum value of xxxx..
20.67824563
K=2.685...
Whoops sorry Calvin 28.
24+ππ−e
42.3779
The answer to life the universe and everything, and also this game, is 42
29.1
π2+ϕ⋅e−10ϕ=14.106...
−1.2i(π⋅e⋅ϕ⋅i)
14.771883793201
38.6603773585
19.91161761
16
Cos(i)×ii
21.415926535...........
pi^pi / e
I would try pi^3, slightly larger than 31
28.16
-6!
10
Interesting idea. I think the answer depends on whether the value of victory is a constant-value 'prize', or a divided-value 'lottery' (In the lottery, the more winners there are, the less money/utility each winner gets). In the constant-value 'prize' model, there exists a Nash-equilibrium at 0 for 2 or more players, so the only rational outcome is for everyone to post 0.
However, I'm not sure this applies to the lottery case. I think it does, but it's a fair bit harder!
But doesn't that assume that everyone else is equally as "rational" as you? As seen by the other 2 entries, neither of them said 0.
Even if you said 0 right now, you would not win.
Yes, Game Theory and Nash-equilibriums rely on the assumption that all players behave rationally. If we don't have any way to reason about our "opponents'" behavior, we have nothing, and so the best we can do is make a wild guess.
109 average as yours is, if not closer, so I don't see how 'estimating the future' can help. As soon as you post on a non-zero board, you forfeit your ability to win to the next poster.
You only get one guess, and anyone who posts after you can always make a guess that's at least as close to theHowever, were one to look at the game thus far, without seeing the rules, I would be forced to conclude that the objective is "Post the most arbitrary and clever combination of constants you can think of", and certainly not "Guess as close as possible to 109 the average of all guesses", and it turns out the former is nigh impossible to reason about with the second objective in mind. Social structures have a knack for forging their own goals, regardless of what the coordinators have dictated :).
I am somewhat highly amused that you are the only person who voted 0. What do you think is your probability of winning with this strategy?
I think that there is a reasonable strategy to help guide your thinking. You may not guarantee that you will win, but you could increase the chances of winning. For example, anyone who voted > 60 is unlikely to win.
I feel like this is tough... and does the closest person get a prize?
Also, is there some way to see the numbers listed chronologically (in order of submission) after the discussion is closed? That would be interesting to look at how, if at all, the guesses changed over time.
The closest person gets bragging rights. I'd see what else I can do.
Hm, I agree that having a record of entries is good. I might edit that in.
Wait so do we start posting already? If so, I'm going for 16π2.
Sorry, I had technical difficulties and was unable to make the comment. I'd record your entry down though.
Some many pis and so many Es. I'm going for 28. I don't know why.
For your entry to be accepted, please post it as a reply to my comment. This allows for easy bookkeeping and consolidation of the entries. Thanks.
FunFact: As far as I know, in the whole of the English Language, the only words that have 3 consecutive repeated letters are "bOOKKEEp" and its other forms. (e.g. "bookkeeping" and "bookkeeper".)
45
Please read the rules. For your entry to be accepted, please post it as a reply to my comment.
This allows for easy bookkeeping and consolidation of the entries. Thanks.
19
Please read the rules. For your entry to be accepted, please post it as a reply to my comment.
This allows for easy bookkeeping and consolidation of the entries. Thanks.
0
Please read the rules. For your entry to be accepted, please post it as a reply to my comment.
This allows for easy bookkeeping and consolidation of the entries. Thanks.