We know that given two non - void sets, say A and B, their Cartesian Product is defined as A×B={(a,b):a∈A,b∈B}.
For eg. If A={1,3} and B={2,4,9}, then their Cartesian product is defined as {(1,2),(1,4),(1,9),(3,2),(3,4),(3,9)}.
I was wondering what if the set A itself consists of ordered pairs, like what if A={(1,5),(1,9),(2,5)} and say B={3,7}, then how do we define the A×B?
One thing that I've observed is that ,in case, if the set that consists of ordered pairs ( n-tuples in general) can be expressed as Cartesian product of simple sets (sets that consists of numbers only), then the overall cartesian product can be found. What I mean is
Say, A={(3,4),(3,7),(2,4),(2,7)} and B={2,5} and A×B is to be found, then one can proceed as follows :
A×B={(3,4),(3,7),(2,4),(2,7)}×{2,5}={3,2}×{4,7}×{2,5}={(2,3,4),(2,3,7),(2,2,4),(2,2,7),(5,3,4),(5,3,7),(5,2,4),(5,2,7)}.
#Combinatorics
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Do the same thing. A×B={(a,b)∣a∈A,b∈B}. It doesn't matter what the sets A and B are.
E.g. you can determine { elephant, zinc}×{21,(1,2)}.
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OK...
Infact, this is the method followed to generate n-ary relations.......