Challenge

This is a challenge to all the Brilliant members. Using symbols make your answer to the question as 6. You can use symbols such as squares, plus, minus etc. An example of $6$ is been done for you.

$0 0 0 = 6$

$1 1 1 = 6$

$2 2 2 = 6$

$3 3 3 = 6$

$4 4 4 = 6$

$5 5 5 = 6$

$6 + 6 - 6 = 6$

$7 7 7 = 6$

$9 9 9 = 6$

And finally $8$ is toughest number where you have to use all the Symbols that you have used in all the above questions.

$8 8 8 = 6$

Please reshare and like this if you can and most important please upload your answer.

#NumberTheory

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

I'll post the first one: $(0!+0!+0!)! = 6$

All right, I'll post the "hard one": $(\sqrt { \frac { 8 }{ \sqrt { .\dot { 8 } } \sqrt { .\dot { 8 } } } } \quad )!=6$ .

Note that $.\dot { 8 } =0.888888....$

Michael Mendrin - 7 years ago

Correct! But for $8$ you made it quite difficult. In a simpler way it can be $8 - \sqrt{\sqrt{8+8}}=6$ . And for $0$ it can also be $(\cos0+\cos0+\cos0)!=6$ .

A Former Brilliant Member - 7 years ago

Well, you threw me off by saying it's so difficult!

Michael Mendrin - 7 years ago

@Michael Mendrin – No, you made it little complex

A Former Brilliant Member - 7 years ago

@A Former Brilliant Member – No, you said it was "toughest" and so I figured that only a tough answer would do. How was i to know that a simpler answer was possible? ??

If nobody else comes up with any of the other answers, I'll post them all pretty soon.

Michael Mendrin - 7 years ago

don't tell me that you have taken it from scam school

Alamuru Ganesh - 7 years ago

These are my answers

$(0!+0!+0!)!=6$

$(1+1+1)!=6$

$2+2+2=6$

$(3\times 3)-3=6$

$(4-(4\div 4))!=6\quad or\quad 4+4-\sqrt { 4 } =6$

$5+(5\div 5)=6\quad or\quad { (5 }^{ 2 }+5)\div 5=6$

$7-(7\div 7)=6\quad or\quad { (7 }^{ 2 }-7)\div 7=6$

$(\sqrt { 8+(8\div 8) } )!=6\quad or\quad 8-\sqrt { \sqrt { 8+8 } } =6$

$(\sqrt { ((9\times 9)\div 9) } )!=6$

Ronak Agarwal - 6 years, 11 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$