Chebyshevs Polynomial

The \(n\)-th Chebyshev polynomial (of the first kind) is usually defined as the polynomial expressing \(\cos(nx)\) in terms of \(\cos(x)\).

Closely related is the polynomial Pn(x)P_n(x) that expresses 2cos(nx)2\cos(nx) in terms of 2cos(x)2\cos(x). This polynomial can be obtained by writing:

xn+xnx^{n} +x^{-n} in terms of x+x1x+x^{-1}.

Indeed, if x=cos(t)+isin(t)x = \cos(t) +i \sin(t), then x+x1=2cos(t)x+x^{-1} = 2\cos(t), while by the de Moivre formula xn+xn=2cos(nt)x^{n}+x^{-n} = 2\cos(nt).

Note that the sum-to-product formula cos[(n+1)x]+cos[(n1)x]=2cos(x)cos(nx)\cos[(n+1)x]+\cos[(n-1)x] = 2\cos(x)\cos(nx), allows us to prove by induction that Pn(x)P_n(x) has integer coefficients, and we can easily compute

P0(x)=2,P1(x)=x,P2(x)=x22,P3(x)=x33x\large P_0(x) = 2, P_1(x) = x, P_2(x) = x^2-2, P_3(x) = x^3-3x

The fact that xn+xnx^n +x^{-n} can be written as a polynomial with integer coefficients in

x+x1x +x^{-1} for all nn can also be proved inductively using the identity

xn+xn=(x+x1)(xn+xn)xn2+x(n2)x^n+x^{-n} = \left(x+x^{-1}\right)\left(x^n+x^{-n}\right) - x^{n-2} + x^{-(n-2)} .

#Algebra #Polynomials #DeMoivre'sFormula

Note by Sauditya Yo Yo
5 years, 10 months ago

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