In a chessboard colouring of the " 2-D plane", every black square has an equal number of white and black squares as neighbours-4 (even sharing a single vertex is counted as a neighbour) . If one did a chessboard colouring of the 3-D space, such that it (the 3-D space) is divided into cubes, and for the 2 planes "vertical" and "horizontal" that every cube belongs to , has a chessboard colouring , what is the number of black neighbouring cubes a black cube has?
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
For consistency, please don't use all-caps and that many exclamation points.
Pls elaborate on the question.. its nt clear that which horizontal and vertical planes u are talking of...
8 neighbours of the same color, if you mean that cubes sharing a vertex are neighbours....and 6 of the opposite color (right, left, up, down, front and back).
2
please answer this. it is very important for me.
Log in to reply
Think of a Rubik's cube in a checkerboard pattern. The (invisible) center cube is the black cube whose neighbors we are counting.
There are 26 small cubes "touching" the center cube in this 3x3x3 arrangement. All the middle edge cubes are black. All the corner (8) and center (6) cubes are white. There are 12 black cubes "touching" the center cube at their edges.