Coaxial Cable!

Consider a co-axial cable which consists of an inner wire of radius aa surrounded by an outer shell of inner and outer radii bb and cc respectively. The inner wire carries a current II and outer shell carries an equal and opposite current. The magnetic field at a distance xx from the axis where b<x<cb<x<c is

(a)(a) μ0I(c2b2)2πx(c2a2)\frac{\mu_{0} I(c^2 - b^2)}{2 \pi x(c^2 - a^2)}

(b)(b) μ0I(c2x2)2πx(c2a2)\frac{\mu_{0} I(c^2 - x^2)}{2 \pi x(c^2 - a^2)}

(c)(c) μ0I(c2x2)2πx(c2b2)\frac{\mu_{0} I(c^2 - x^2)}{2 \pi x(c^2 - b^2)}

(d)(d) 00

Note by Advitiya Brijesh
8 years ago

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12 votes

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Comments

This question is based on the application of Ampere's circuital law. Give it a try at least. :)

Pranav Arora - 8 years ago

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thnx buddy bt i had already done it... it was the question that i felt was good to be posted because i got stuck in this particular question!!!!

Advitiya Brijesh - 8 years ago

with your help... :)

Advitiya Brijesh - 8 years ago

hey... Is your AGE = 14 ...................?? Please Reply

Vamsi Krishna Appili - 8 years ago

the answer will be C

Farhan Masood Laskar - 8 years ago

I think it will be option c)!!!

Sorry, option b)!!!

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C

magnetic field due to inner wire: mu I / (2 pi x)

current between b and x: - I (x^2 - b^2) / (c^2 - b^2)

magnetic field due to current between b and x: - [mu I / (2 pi x)] [(x^2 - b^2) / (c^2 - b^2)]

magnetic field at x: [mu I / (2 pi x)] [(c^2 - x^2) / (c^2 - b^2)] which is C

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Ah Ramon, I was waiting for Advitiya to post his attempt. You should not have given the solution. It would be a great experience for Advitiya if he solved this by himself. :)

Pranav Arora - 8 years ago

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i rarely give away full solutions. usually i just give hints. i just feel like giving the solution this time.

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@Ramon Vicente Marquez hints...this doesn't even require any hint!!

sudheesh srivastava - 8 years ago

8.02x, huh?

Ahaan Rungta - 8 years ago
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