Complex made easy

For beginners (like me) in complex here are few interesting formulae

$i=\sqrt { -1 }$

${ i }^{ 4n+2 }\quad =\quad -1$

${ i }^{ 4n }\quad =\quad 1$

${ i }^{ 4n-1 }\quad =\quad -i$

${ i }^{ 4n+1 }\quad =\quad i$

Here $n\quad belongs\quad to\quad integers$

You can use this to calculate i raised to any power

PS: Try proving them

#Algebra

Easy Math Editor

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`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
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Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$