confused by the photo electric effect

during photo electric effect electrons are emitted what happens to the atom which emitted electron and what will be the stability of the atom

#Physics #ElectricityAndMagnetism #Advice

Easy Math Editor

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Comments

Photo- electric effect is the phenomenon of certain metals . We know that metallic atoms like to lose electrons so that they achieve stability because they are closer to having their octet complete .So the atoms after losing electrons turn into cations and get stable . Also during photo-electric effect, the free electrons from the metal surface are emitted . This means that the metallic atoms have already lost their electrons and when light is incident on the metal surface those free electrons gets emitted .

Shubham Barua - 7 years, 8 months ago

A photon with the specific discrete energy level required by the atom to change the valence electron's state to a higher state, will change the orbital of that electron. In the case of the photoelectric effect, the electron's energy level will change to the infinitesimally larger energy level than the maximum possible energy level of that atom (maximum orbital); hence emitting the electron from the atom. Once the atom has lost this electron, it simply becomes ionized and is in need of another electron. This electron could be a free electron or it could be a valence electron from another atom in which they may form a bond. Though in the case of a larger chunk of metal; this is generally disregarded.

Joel Jablonski - 7 years, 8 months ago

You will get to know In ur Xth Standard ., If u are in AP ., then the Explanation is in 211th page of TEXTBOOK.

Vamsi Krishna Appili - 7 years, 8 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$