Confusing

Under Kinematics re motorcycle acceleration/deceleration, if you are trying to teach people about Kinematics you should make your diagrams agree with your math. The graph of velocity vs time at acceleration max is backward! Assuming the bike starts (as the problem describes) at velocity 0 and accelerates at a lesser rate than it decelerates back to zero velocity, the slope of the first line must be lower than the slope of the second line (at T). So while the max velocity reached is correct the path to the answer is confusing.

John

#Mechanics

Easy Math Editor

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Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$