Connection between your age and periodic table

Hi I brilliant members made this note because I think it would be fun and it will help us socialize a little I guess.So getting back to the point the challenge is to connect your age to any math related events or the periodic table etc.

#Science #FUN #Funny #Everybody #PeriodicTable

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

@Mardokay Mosazghi, I too am Phosphorous but I will become Sulphur on $18^{\text{th}}$ .

Ameya Salankar - 7 years, 1 month ago

LOL :D

Krishna Ar - 7 years, 1 month ago

Ha Ha

Mardokay Mosazghi - 7 years, 1 month ago

But on brilliant, your age is 14?

Krishna Ar - 7 years, 1 month ago

@Krishna Ar – Yeah I don't know how to change it.

Mardokay Mosazghi - 7 years, 1 month ago

@Mardokay Mosazghi – Click the cog icon next to your name and click account settings. Browse through al the tabs till you get the right one.

Sharky Kesa - 7 years, 1 month ago

@Sharky Kesa – Thanks by the way what time is it in Australia now

Mardokay Mosazghi - 7 years, 1 month ago

@Mardokay Mosazghi – 8:44 PM

Sharky Kesa - 7 years, 1 month ago

I am Gadol, which in Hebrew can mean, "great", or "hilarious", depending on who you ask. Look up the metal element that starts with gadol.

Michael Mendrin - 7 years, 1 month ago

I am an element which has 6 allotropes(identified by each one's colour) and forms almost 10 acids( or oxoacids to be precise). I am also never found as a free element in earth. What am I?.......I am phosphorous!!!

Krishna Ramesh - 7 years, 1 month ago

i became cCl i became Cl today....

Max B - 7 years, 1 month ago

Base (me) is a better base to write terminating decimals if you think about it. I am magnesium. I am a dozen. I am a composite number, the smallest number with exactly six divisors. I am also a highly composite number, the next one being 24. I am the first composite number of the form p^2q; a square-prime. I am an factor sum of 16. Accordingly, I am the first abundant number (in fact a superabundant number). Only 2 other square primes are abundant (18 and 20). Who am I? (These should be enough clues)

Sharky Kesa - 7 years, 1 month ago

You spelt periodic wrong.

Sharky Kesa - 7 years, 1 month ago

sorry going to edit it

Mardokay Mosazghi - 7 years, 1 month ago

I don't think you can.

Sharky Kesa - 7 years, 1 month ago

@Sharky Kesa – Ah it is the title dang it

Mardokay Mosazghi - 7 years, 1 month ago

Did not connect my age, but my birthday

$25/10/1997\ :\\ 2*5=10\\ 5^2=25\\$ Also $10$ is the first two digit number in any base.

My age is $16$ and nobody would be able to light a matchstick without me.

Also my name abbreviated is $mgh$ one of the most used Potential energies in Phsics.

In chemistry, $MgH_2$ is a potential Hydrogen Fuel Storer.

Megh Parikh - 7 years, 1 month ago

how to actually get the relation?

Saketh Ramanujam - 7 years ago

I am $\boxed{P}$ , but in a week I shall be $\boxed{S}$ . The lightest containing both of those elements is sulfanylidenephosphanide, which has the structure $[P-]=S$ (a phosphorus ion double bonded to a sulphur atom).

A Former Brilliant Member - 6 years, 11 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$