Conservation of energy in Interference of light

I have a question. The question is 'where does the energy go when a Destructive Interference happen?' I googled the question! All I came to know is that the energy lost in the destructive interference adds up to the energy of constructive interference! I find it hard to believe when I consider the Young's Double Slit Experiment. Please help me in this considering the Double Slit Experiment.

#Physics #HelpMe!

Easy Math Editor

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Comments

Ask a simpler question first. Where does the particle go in the double slit experiment? The total probability of finding the particle before it hits the slits is 1, and the total probability after it hits the slits is also 1. All that's happened is that the distribution of the probability of where the particle is has changed in a different way than you might think classically (but it's more likely to be found in the areas where there was constructive interference). If you can come to grips with the total probability of the particle still being 1, then you should be able to realize that you have lost neither particle nor the total energy of the particle in the double slit experiment.

David Mattingly Staff - 8 years, 3 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$