Counting problem with a few restrictions (combinatorics)

Let's take Keno for example:

From number 1 to 80, there are (8020)=3,535,316,142,212,174,320\dbinom{80}{20} = 3,535,316,142,212,174,320 ways the casino can draw 20 numbers out of 80.

Given that the sum of the 20 numbers drawn is nn, how many combinations satisfy the following conditions:

  • x1+x2+x20=nx_1+x_2\ldots+x_{20} = n
  • x1,x2,,x20x_1,x_2,\ldots,x_{20} are distinct
  • 1xi801 \leq x_i \leq 80

Eg. If n=210n = 210, which is the minimum sum, 1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20=2101+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20 = 210, therefore there is only one possible combination for the sum of 20 numbers to be 210.

What about, say, n=896n = 896? I have tried stars and bars but not really sure how to apply the distinct restriction.

#Combinatorics

Note by Lim Sy
3 years, 8 months ago

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