Cut Right Triangle Problem

So, the other day, i was programming something and got a geometry doubt. I apologize for the bad drawing. But anyway, this is a 90-45-45 triangle with legs of 1 unit. It is cut from the 45° point to the exact middle of each of the legs. The red lines are perpendicular to the legs and extends till the meeting point of both the cuts. What is the length of the red lines (only one of them as they form a square) ?

(diagram not to scale)

Note by Akshaj Gopalakrishnan
2 years, 2 months ago

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Comments

I am getting the lenghts to be 13\displaystyle \frac{1}{3}

Aaghaz Mahajan - 2 years, 2 months ago

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Bhai muje apni I'd de sakta hai plzz..

Mohit . - 1 year, 4 months ago

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kyon kya kaam hai?? also, do I know you??

Aaghaz Mahajan - 1 year, 4 months ago

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@Aaghaz Mahajan Na, muje 1 course ke aaghe ke chapter dekhne the or ye free ni hai tab.

Mohit . - 1 year, 4 months ago

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@Mohit . main premium nhi hun, aur main course nhi dekhta…..

Aaghaz Mahajan - 1 year, 4 months ago

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@Aaghaz Mahajan OK thanks BTW :D

Mohit . - 1 year, 4 months ago

Simply use co-ordinate geometry.....

Aaghaz Mahajan - 2 years, 2 months ago

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Could you please explain that? I am really interested.

Akshaj Gopalakrishnan - 2 years, 2 months ago

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Here is an outline of my method.....

Consider the origin to be the right angled vertex. The remaining two points are located on (1,0) & (0,1)\left(1,0\right)\ \&\ \left(0,1\right)
Hence, the midpoints will be located at (12,0) & (0,12)\left(\frac{1}{2},0\right)\ \&\ \left(0,\frac{1}{2}\right)
Now, simply write the equations of the lines joining the points and you'll arrive at the answer......

Aaghaz Mahajan - 2 years, 2 months ago

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@Aaghaz Mahajan Thanks!

Akshaj Gopalakrishnan - 2 years, 2 months ago

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@Akshaj Gopalakrishnan You are welcome!!

Aaghaz Mahajan - 2 years, 2 months ago

You can also use similar triangles. Let the length of the red lines be xx. Consider the right triangle with the vertical red line as it's vertical leg. This right triangle has height xx and base length 1x1 - x, and is similar to the right triangle with height 1/21/2 and base length 11. By similarity we then have that

x1x=1/212x=1x3x=1x=13\dfrac{x}{1 - x} = \dfrac{1/2}{1} \Longrightarrow 2x = 1- x \Longrightarrow 3x = 1 \Longrightarrow x = \dfrac{1}{3}.

Brian Charlesworth - 2 years, 2 months ago
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