Decimal parts of multiples

For a real number xx, let f(x)f(x) be a function such that f(x)=xxf(x) = x - \lfloor x \rfloor; and let A(x)A(x) be a set such that A(x)={f(xn):nN}A(x) = \{f(xn) : n \in \mathbb{N} \}.

Prove the following:

(1) xx is rational if and only if A(x)A(x) is finite;

(2) xx is irrational if and only if A(x)A(x) is dense in the interval [0,1)[0,1).

Have fun :)

#Algebra #Sets #IrrationalNumbers #Decimals #FloorFunction

Note by Ariel Gershon
6 years ago

No vote yet
1 vote

  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

  • Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
  • Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
  • Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
  • Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

Suppose A(x) A(x) is finite. Then by the Pigeonhole Principle, there are two distinct integers m m and n n such that f(xm)=f(xn) f(xm) = f(xn) . So xmxn=k xm-xn = k is an integer. Then x=kmn x = \frac{k}{m-n} is rational.

Suppose A(x) A(x) is dense in [0,1) [0,1) . Then it is certainly infinite. So x x can't be rational, by (1).

What remains is to show that if x x is irrational, then A(x) A(x) is dense in [0,1) [0,1) .

Patrick Corn - 6 years ago

Log in to reply

You can do this by the Pigeonhole Principle as well:

http://math.stackexchange.com/questions/272545/multiples-of-an-irrational-number-forming-a-dense-subset

Patrick Corn - 6 years ago

We see that f(x)={x}f(x) = \{x\}, i.e. it is the fractional part of xx.

(1) \longrightarrow In this direction we assume that xx is rational and try to prove A(x)A(x) is finite. Since xx is rational, we can write it as x=pqx = \frac{p}{q} where pp and qq are coprime integers and qq is not zero.

Claim: A(x)A(x) will have exactly qq elements.

The elements in A(x)A(x) will be {pq},{2pq},{3pq},{4pq},\big \{\frac{p}{q} \big \}, \big \{\frac{2p}{q} \big \}, \big \{\frac{3p}{q} \big \}, \big \{\frac{4p}{q} \big \}, \ldots .

Since pp and qq are integers, these terms can be written as p mod qq,2p mod qq,3p mod qq,4p mod qq,\frac{p ~\bmod~ q}{q}, \frac{2p ~\bmod ~ q}{q}, \frac{3p ~\bmod ~ q}{q}, \frac{4p ~\bmod~ q}{q}, \ldots . There can be only qq such terms, viz 0q,1q,2q,q1q\frac{0}{q}, \frac{1}{q}, \frac{2}{q}, \ldots \frac{q-1}{q}. Since qq is a finite number, A(x)A(x) also has a finite number of elements.

Pranshu Gaba - 6 years ago
×

Problem Loading...

Note Loading...

Set Loading...