Derivatives of Trigonometric Functions

sin(x)=cos(x)cos(x)=sin(x)tan(x)=sec2(x)cot(x)=cosec2(x)sec(x)=sec(x)tan(x)cosec(x)=cosec(x)cot(x)arcsin(x)=11x2arccos(x)=11x2arctan(x)=11+x2arccot(x)=11+x2arcsec(x)=1xx21arccosec(x)=1xx21\begin{aligned} \sin^\prime(x)&=\cos(x)\\ \cos^\prime(x)&=-\sin(x)\\ \tan^\prime(x)&=\sec^2(x)\\ \cot^\prime(x)&=-\cosec^2(x)\\ \sec^\prime(x)&=\sec(x)\tan(x)\\ \cosec^\prime(x)&=-\cosec(x)\cot(x)\\ \arcsin^\prime(x)&=\frac{1}{\sqrt{1-x^2}}\\ \arccos^\prime(x)&=-\frac{1}{\sqrt{1-x^2}}\\ \arctan^\prime(x)&=\frac{1}{1+x^2}\\ \operatorname{arccot}^\prime(x)&=-\frac{1}{1+x^2}\\ \operatorname{arcsec}^\prime(x)&=\frac{1}{x\sqrt{x^2-1}}\\ \operatorname{arccosec}^\prime(x)&=-\frac{1}{x\sqrt{x^2-1}}\\ \end{aligned}

#Calculus

Note by Gandoff Tan
1 year, 6 months ago

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Comments

How do you center-align the equations?

Adhiraj Dutta - 1 year, 5 months ago

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use \begin{aligned} a&=b \ \ c&=d \end{aligned}

Gandoff Tan - 1 year, 5 months ago

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or \ [ and \ ]

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