One day, I was asleep, and in my dream yesterday, I dreamt that I was playing with factorials. I then got this sudden revelation of a weird formula:
\(\LARGE{\frac{1! × 2! × ... × n!}{1 × 2 × ... × 2n}}\)
Simplifying this, we can get:
Where is the and is the superfactorial
When we substitute with different values, we gain these numbers:
I decided to plot this using WolframAlpha, but I do not have the Pro Version, so I plotted a smaller range of values instead (because I was bored a lot...)
Does this graph or number set have any special value to them? I was just bored, but maybe you can find a better explanation for these numbers. I would love to see what random facts you can gain about these weird numbers that came to me in a dream...
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2^{34}
a_{i-1}
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@Vinayak Srivastava, @Mahdi Raza, @Yajat Shamji, @Páll Márton
Do these numbers look like something similar, like any other number?
Please give in a small research and let me know...
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@Hamza Anushath, Wait! I got it! I know what's special about these numbers! I figured it out!
They all are.....
Reply to this comment to know the answer.
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The answer is.....
Decimal numbers (Irrational I think, but could be rational)
Wow! This is my 2nd biggest discovery after I discovered that 1+1 = 2!
LOL, XD!!! LOL, XD!!! LOL, XD!!! LOL, XD!!!
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@Yashvardhan Pattanashetti
YesPlus, they are rational numbers, as they repeat their digits forever
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Maybe you should have written:
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@Vinayak Srivastava!
Nice one,@Yashvardhan Pattanashetti's name?
Maybe replace the Fermat withWhat do you think?
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I guessed you made a discovery in my dreams. I was still awake around 10:30 when I suddenly thought about new problem series:
Hexadecimal clocks
Binary clocks
Algebraic binary locks
Algebraic hexadecimal locks
Basically, I am a walking-talking mathematician as well. @Hamza Anushath, @Yashvardhan Pattanashetti, @Páll Márton
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Woah, are you a walking... talking... mathematician!?!
I am just a minor mathematician...
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Not the zombie type of walking-talking, though.
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We get that. lol
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Do you think I am a walking-talking mathematician?
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What do you think about my new problem series that I mentioned?
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Just thought of two more problem series:
Hexadecimal locks
Binary locks
What do you think, @Yashvardhan Pattanashetti?
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Nice!! Looking forward to it.
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5 mins.
Posting the first hexadecimal lock problem inLog in to reply
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The only thing I was able to link this to was the superfactorial, defined by Neil Sloane and Simon Plouffe to be the product of incrementing factorials (the numerator in your expression). Using the notation for a superfactorial, your expression could simplify to:
(2n)!sf(n)
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Thanks a lot @David Stiff! If you could, could you tell me whether the graph I generated is correct or not...?
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You're welcome Hamza!
I wrote some Python code to generate a graph of this expression, and both the numerical values and the graph are identical to those you calculated. I only used the superfactorial form however, not the more general Barnes G-function. I don't think I can post pictures in a reply, but here are the first 10 values I got:
1,0.5,0.083,0.016,0.007142857142857143,0.009523809523809525,0.05194805194805195,1.4385614385614385,241.67832167832168
I find it interesting that the graph first descends, bottoms out at n=4 and then ascends again, rocketing up at n=6.
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@David Stiff
Thanks a lot once againP.S. We can post pictures in a comment by uploading it in a note and copying that code and pasting it here, the code starting with ![]
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You can't generate a graph using this function, @David Stiff, @Hamza Anushath
I was just thinking, I could simplify your top equation:
2n!n!!
Try it, @Hamza Anushath
n!! is the double factorial. @Hamza Anushath
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@Yajat Shamji, it's not the double Factorial, it is actually a superfactorial...
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Oops. But did you try it?
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@Yajat Shamji
Yes, and very sorry, it brought a wrong valueLog in to reply