Discovery in the '100-Day Challenge'

In Day 82:

According to this picture by @David Vreken , we know that if the size of the table is a×ba\times b, then the total number of collisions is:

(lcm(a,b)a1)+(lcm(a,b)b1)=a+bgcd(a,b)2(\frac{{\rm lcm}(a,b)}{a}-1)+(\frac{{\rm lcm}(a,b)}{b}-1)=\frac{a+b}{\gcd{(a,b)}}-2


In Day 83:

According to my method, if the cup capacity is aa and bb respectively, and the cup is empty at the beginning, then the total plan that can be poured is

a+bgcd(a,b)\frac{a+b}{\gcd{(a,b)}}


These two formulas have similarities, what is the relationship between them?

Note by Zhiqian Chen
9 months, 3 weeks ago

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Comments

Same diagram

A Former Brilliant Member - 9 months, 3 weeks ago
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