After solving all 6 problems, I just remembered a very fast, easy and awesome way to solve other problems like these 6 problems. (Note: You can easily prove my equations!)
Back to our easy equations:
1=12
1+2+1=22
1+2+3+2+1=32
...
And:
1=1
1+2=22×(2+1)
1+2+3=23×(3+1)
...
These are very simple right, I think you can prove them easily. But there is a question: Can you calculate quickly this sum: 1+4+7+...+34=?
My answer is: Yes, you can! But how?
Using this sum above
First, calculate the total terms of this sum:
Numbers of Terms = The difference between each term( The last term - The first term)+1.
In this equation, the number of terms is: 334−1+1=12
Our first step is completed, now move to the next step
To sum this equation, use this:
The sum =2(The first term + The last term)×Number of terms
So in this equation:
The sum is: 2(34+1)×12=210
This is my solution, and you can use it in all arithmetic series. I hope to discuss more with all of you.
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Note: To use latex, you have to place it within the brackets \ ( code \ ), with spaces removed. Also, you don't need to use \quad to space out text. Just leave them outside of the brackets. If you want to include text, I would suggest using \text{ XXX } instead, as this makes it display as per normal, instead of italicised.
I edited the first few paragraphs of your note, to give you an example. You can edit it to see the changes that I made.
Oh, thank you. I am just a newbie here!
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Looks great! You are a fast learner.
Thank you for your help!