The link to the Round 2 Paper for this year's Singapore Mathematical Olympiad is here. The Round 2 competition takes place just yesterday (28 June) so it's pretty new.
Here's the place to discuss the answers to these qns. :) So for those interested to try them or discuss them, feel free to do so!
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Comments
Still weak at solving symmetric systems... Number 2....
If anyone requires, the SMO Junior Round 2 2014 Qns can be found here
Answer to second is (0,0,00 and (4,4,4)
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Question asked for only positive reals.
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Sorry, Then only (4,4,4)
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a≥b≥c>0. Then a+b≥a+c, yet ab≥bc, which implies a+c≥a+b instead, so b=c. Similarly, a=b=c. And we are done.
Something like WLOGLog in to reply
@Victor Loh did you do that to?
I think that's itx=a,y=b,z=c . The you get 3 equations. Try to find ab expression involving just one variable. So, we get x(x−2)(x12−3x11+6x10−14x9+22x8−28x7+37x6−35x5+26x4−21x3+14x2−12x+8)=0. . Now this gives x=2,x=0. So, we get a=4,0. So, leaving 0, we get the desired result
An easy way is to substituteLog in to reply
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I took the Junior paper though, and it was easier than I had thought previously, to be honest. I solved all 5 questions :)
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Good luck to all who took the SMO! Wish you all the best! :D
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How does Question 4 pop out without much effort at all
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5 was pretty obvious though... For 2 I used another method.
Q3 just spam lah hahah
Wut! For 4 you have to prove that a,b and c HAVE to be equal man.
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