I was thinking recently and got stuck on a strange problem:
Take the fourth route if both sides:
I don't know what the problem is: have I made a mistake? Or is their a way of explaining this that I am not aware of? Please leave a comment if you have any ideas!
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4=x4 has 4 solutions for x. They are like roots for polynomials. These roots are ±2 and ±−2.
btw I edited the Latex of your note.
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Thank! I still won't pretend I undestand how that rule accounts for the other possible answers to that (i.e. Wouldn't that mean there were 4 answers to root-2, one of which being root 2?). But thanks that's really interesting-and thanks for the editing I'm really bad at that kind of thing!
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I'll give a simpler example: x2=4 would have 2 solutions for x, namely −2 and 2. Even though (−2)2=4 and (2)2=4, −2=2