does 2=-2?

I was thinking recently and got stuck on a strange problem:

(2)2=4=(2)0.5×4=((2)0.5)4=4=24(-2)^{2}=4=(-2)^{0.5\times4}=((-2)^{0.5})^{4}=4=\sqrt{2}^{4}

Take the fourth route if both sides:

(2)0.5=2(-2)^{0.5}=\sqrt{2}

2=2\sqrt{-2}=\sqrt{2}

2=2-2=2

I don't know what the problem is: have I made a mistake? Or is their a way of explaining this that I am not aware of? Please leave a comment if you have any ideas!

#Indices #Confusing #Squaroot #Mathsisstrange

Note by Katie Marsden
6 years, 2 months ago

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Comments

4=x44=x^{4} has 44 solutions for xx. They are like roots for polynomials. These roots are ±2\pm\sqrt{2} and ±2\pm\sqrt{-2}.

btw I edited the Latex of your note.

Julian Poon - 6 years, 2 months ago

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Thank! I still won't pretend I undestand how that rule accounts for the other possible answers to that (i.e. Wouldn't that mean there were 4 answers to root-2, one of which being root 2?). But thanks that's really interesting-and thanks for the editing I'm really bad at that kind of thing!

Katie Marsden - 6 years, 2 months ago

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I'll give a simpler example: x2=4x^{2} = 4 would have 2 solutions for xx, namely 2-2 and 22. Even though (2)2=4(-2)^{2}=4 and (2)2=4(2)^{2}=4, 22-2\neq 2

Julian Poon - 6 years, 2 months ago
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