Does it have any value?

Try if you can find value of below expression: \[\sqrt{1+\sqrt{\sqrt{2+\sqrt{\sqrt{\sqrt{3+\sqrt{\sqrt{\sqrt{\sqrt{4+\sqrt{\sqrt{\sqrt{\sqrt{\sqrt{5...}}}}}}}}}}}}}}}=?\]

Any solution will be appreciated

#Algebra

Note by Zakir Husain
11 months, 3 weeks ago

No vote yet
1 vote

  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

  • Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
  • Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
  • Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
  • Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

I think it is almost equal to 1.531.53

Above expression can be written as 1+42+83+....\sqrt{1 + ^4\sqrt{2 + ^8\sqrt{3 + ....}}}

So, the rth^{th} root is 2r2^r which is increasing exponentially whereas the value inside root is increasing linearly. So, it will be equal to 11 after each root is simplified, so finally it will come as 1+1.41.53\boxed{\sqrt{1 + 1.4} \approx 1.53}. Hope it helps.

Aryan Sanghi - 11 months, 3 weeks ago

Log in to reply

even 1+2+3>2\sqrt{1+\sqrt{\sqrt{2+\sqrt{\sqrt{\sqrt{3}}}}}}>\sqrt{2}

Zakir Husain - 11 months, 3 weeks ago

Log in to reply

I know, I mean it will converge near 1.53 approx.

Aryan Sanghi - 11 months, 3 weeks ago

Log in to reply

@Aryan Sanghi Please explain your answer.

A Former Brilliant Member - 11 months, 3 weeks ago

Log in to reply

@A Former Brilliant Member Actually I'll try but I guess I can't explain better. @Zakir Husain can you please help?

Aryan Sanghi - 11 months, 3 weeks ago

Log in to reply

@Aryan Sanghi I myself don't have any idea, it came to my mind and just stuck there. That's why I have wrote this note.

Zakir Husain - 11 months, 3 weeks ago

@Aryan Sanghi Please

A Former Brilliant Member - 11 months, 3 weeks ago

Log in to reply

@A Former Brilliant Member See, the rth has its root value 2r2^r, isn't it? Now, the number inside the root is only rr. So, we can see that value of root is increasing exponentially whereas the number inside root is increasing linearly. So, the root will take it closer and closer to 1 as we move right.

So, we could ignore values more than 3. So, answer is 1+42+831.53\sqrt{1 + ^4\sqrt{2 + ^8\sqrt{3}}} \approx 1.53

Hope I explained well.

Aryan Sanghi - 11 months, 3 weeks ago

Log in to reply

@Aryan Sanghi Oooo,i've understood.I thought that you have done some substitution.Nice method of approximaton..are you preaparing for jee mains???

A Former Brilliant Member - 11 months, 3 weeks ago

Log in to reply

@A Former Brilliant Member Yes, for JEE mains and advanced.

Aryan Sanghi - 11 months, 3 weeks ago

Log in to reply

@Aryan Sanghi Nice

A Former Brilliant Member - 11 months, 3 weeks ago

Is it correct now @Zakir Husain, I have edited the solution.

Aryan Sanghi - 11 months, 3 weeks ago

Log in to reply

@Aryan Sanghi It is 1.53...\approx1.53...

Zakir Husain - 11 months, 3 weeks ago
×

Problem Loading...

Note Loading...

Set Loading...