1) How to prove this one: 2a+b+2b+c+2c+a \frac{2}{a+b} + \frac{2}{b+c} + \frac{2}{c+a} a+b2+b+c2+c+a2 ≤\le≤ 1a+1b+1c \frac{1}{a} + \frac{1}{b} + \frac{1}{c}a1+b1+c1
2) Eliminate t: x=10(t−sint)x=10( t-\sin t)x=10(t−sint) and y=10(1−cost)y=10(1-\cos t)y=10(1−cost)
Note by Baibhab Chakraborty 2 months, 3 weeks ago
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This is a equation of a cycloid . I have eliminated ttt but equation is Messier. Generally , x=r(t−sin(t))x=r(t-\sin(t))x=r(t−sin(t))
,and y=r(1−cos(t)) ⟹ cos(t)=1−yr ⟹ 1−sin2(t)=1−yr→ay=r(1-\cos(t))\implies \cos(t)= 1-\dfrac{y}{r} \implies \sqrt{1-\sin^2(t)} = 1-\dfrac{y}{r} \rightarrow{a}y=r(1−cos(t))⟹cos(t)=1−ry⟹1−sin2(t)=1−ry→a
And also t=cos−1(1−yr)t=\cos^{-1} (1-\dfrac{y}{r})t=cos−1(1−ry)
From xxx we can find sin(t)=t−xr=cos−1(1−yr)−xr\sin(t)= t-\dfrac{x}{r} = \cos^{-1}(1-\dfrac{y}{r})-\dfrac{x}{r}sin(t)=t−rx=cos−1(1−ry)−rx
Putting this on aaa we will find equation is x2+y2r2−2r(xcos−1(yr−1)+y)+(cos−1(yr−1))2=0\dfrac{x^2+y^2}{r^2} -\frac{2}{r}(x \cos^{-1}(\dfrac{y}{r}-1)+y) +(\cos^{-1} (\dfrac{y}{r}-1))^2 =0r2x2+y2−r2(xcos−1(ry−1)+y)+(cos−1(ry−1))2=0
Please note that I am actually trying to derive the equation of the path traced by a point fixed on a rolling body in pure rolling in space. Please help, I am a novice.
Ok thank you sir so much.
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Thanks bro . But I am not a sir!;)
.
Is there any available facility of private chat in brilliant? Just intrigued.
No, there is no such feature (tho there should be lol)
@Percy Jackson I found a solution to the first one: I had thought of using H.M but couldn;t end doing the problem. Its as follows:
a+b2≥2aba+b \frac{a+b}{2} \ge \frac{2ab}{a+b}2a+b≥a+b2ab [ A.M ≥\ge≥ H.M ]
a+b2ab≥2a+b \frac{a+b}{2ab} \ge \frac{2}{a+b}2aba+b≥a+b2
1a+1b2≥2a+b \frac{\frac{1}{a} + \frac{1}{b}}{2} \ge \frac{2}{a+b}2a1+b1≥a+b2
Σ1a+1b2≥Σ2a+b \Sigma \frac{\frac{1}{a}+\frac{1}{b}}{2} \ge \Sigma \frac{2}{a+b}Σ2a1+b1≥Σa+b2
2a+b+2b+c+2c+a≤1a+1b+1c \frac{2}{a+b} + \frac{2}{b+c} + \frac{2}{c+a} \le \frac{1}{a} + \frac{1}{b} + \frac{1}{c}a+b2+b+c2+c+a2≤a1+b1+c1
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Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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\boxed{123}
Comments
This is a equation of a cycloid . I have eliminated t but equation is Messier. Generally , x=r(t−sin(t))
,and y=r(1−cos(t))⟹cos(t)=1−ry⟹1−sin2(t)=1−ry→a
And also t=cos−1(1−ry)
From x we can find sin(t)=t−rx=cos−1(1−ry)−rx
Putting this on a we will find equation is r2x2+y2−r2(xcos−1(ry−1)+y)+(cos−1(ry−1))2=0
Please note that I am actually trying to derive the equation of the path traced by a point fixed on a rolling body in pure rolling in space. Please help, I am a novice.
Ok thank you sir so much.
Log in to reply
Thanks bro . But I am not a sir!;)
.
Log in to reply
Is there any available facility of private chat in brilliant? Just intrigued.
Log in to reply
No, there is no such feature (tho there should be lol)
@Percy Jackson I found a solution to the first one: I had thought of using H.M but couldn;t end doing the problem. Its as follows:
2a+b≥a+b2ab [ A.M ≥ H.M ]
2aba+b≥a+b2
2a1+b1≥a+b2
Σ2a1+b1≥Σa+b2
a+b2+b+c2+c+a2≤a1+b1+c1