Electrostatics doubt

Consider two large and thin conducting plates, separated by a small distance. A charge Q is placed on one of the plates. The two plates are connected by a conducting wire. Find the final charge distribution.

#ElectricityAndMagnetism

Easy Math Editor

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`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
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`\sum_{i=1}^3`	$\sum_{i=1}^3$
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Comments

I guess I got it : Q/2 on both outer surfaces, 0 on both inner surfaces.

Venkata Karthik Bandaru - 4 years, 3 months ago

That is correct.

Kushal Patankar - 4 years, 3 months ago

Yep its an easy one . its a direct consequence of Gauss's law and laws of conductors under electrostatic condition . They should be equipotential as connected by a wire , Total charge will remain conserved since there is no external source of charge and Gauss's law will do it.

Prakhar Bindal - 4 years, 3 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$